A football punter accelerates a 0.59 kg football from rest to a speed of 10 m/s in 0.19 s.?

A football punter accelerates a 0.59 kg football from rest to a speed of 10 m/s in 0.19 s.

What constant force does the punter exert

on the ball?

Answer in units of N.

3 Answers

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  • MyRank
    Lv 6
    4 weeks ago

    Given,

    Mass (m) = 0.59kg 

    Time (t) = 0.19sec 

    Speed (v) = 10m/sec 

    Force (F) = ? 

    We know that:- 

    Force (F) = Mass (m) x Acceleration (a) 

    Force (F) = 0.59kg x speed (v) / Time (t) = 0.59kg x 10m/sec / 0.19sec Force (F) = 0.59kg x 52.63m/sec² = 31.05kg.m/sec² ∴ Force (F) = 31.05N 

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  • 1 month ago

    use the newton second law of motion

    F=ma

    m=0.50kg

    a=10/0.19

    a=52.63

    F=0.50*52.63

    F=26.35N

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  • Anonymous
    1 month ago

    F = m*a = m*ΔV/Δt = 0.59*10*100/19 = 31 N

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