A baseball (m =150 g) is traveling at 40.0 m/s how much work must be done to stop the ball?

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  • MyRank
    Lv 6
    1 month ago

    Given,

    Mass (m) = 150g = 0.15kg

    Speed (v) = 40m/sec

    Work (w) = ?

    The work done will change into Kinetic Energy, when the ball brought to stop

    So, work done (w) = Kinetic Energy (K.E) = ½mv²

    Work done (w) = ½mv² = ½ x 0.15kg x (40m/sec)²

    = ½ x 0.15kg x 1600m²/sec²

    = 120Joules.

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  • oubaas
    Lv 7
    1 month ago

    W = KE = 0.15*40^2/2 = 800*0.15 = 120 joule

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  • Mangal
    Lv 4
    1 month ago

    Kinetic energy = ½mv² = ½(0.15 kg)(40 m/s)² = 300 J

    300 J energy will be required to stop the baseball (then its KE will be 0)

    Ans = 300 J

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  • Anonymous
    1 month ago

    3.75

    I'm not sure if my answer are is right

    .

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