Joe asked in Science & MathematicsPhysics · 1 month ago

Photons with a frequency of 1.0 × 1020 hertz strike a metal surface.?

If electrons with a maximum kinetic

energy of 3.0 × 10–14

joule are emitted, the work

function of the metal is

A) 1.0 × 10–14 J

B) 2.2 × 10–14 J

C) 3.6 × 10–14 J

D) 6.6 × 10–14 J

1 Answer

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  • Mangal
    Lv 4
    1 month ago

    First calculate the energy content in the photon.

    E = hf ... ... ... ... // f : fequency of radiation, h: Plank's constant

    E = (6.63 × 10^–34)(1 x 10^20) = 6.63x10^-14 J

    Photon gives energy to an electron. Some energy (work function) is used in liberating the electron from the atom and the rest is received by the electron in the form of Kinetic energy. Thus,

    (Kinetic energy) = (Photon energy) - (Work function)

    ................ 3x10^-14 = 6.63x10^-14 - Wf

    ................ Wf = 3.63^-14 J

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