Explain this problem please?

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1 Answer

Relevance
  • 3x = 7x^2

    x = 0

    3 = 7x

    x = 3/7

    3x > 7x^2 along the domain

    (3x - 7x^2) * dx , x = 0 , x = 3/7

    Integrate

    (3/2) * x^2 - (7/3) * x^3 , x = 0 , x = 3/7

    (3/2) * ((3/7)^2 - 0^2) - (7/3) * ((3/7)^3 - 0^3) =>

    (3/2) * (9/49) - (7/3) * (27/343) =>

    (3/2) * (9/49) - (7/3) * (3/7) * (3/7)^2 =>

    (3/2) * (9/49) - 1 * (9/49) =>

    (3/2 - 1) * (9/49) =>

    (1/2) * (9/49) =>

    9/98

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