A force ~F=Fxˆı+Fyˆj acts on a particle that undergoes a displacement of ~s=sxˆı+syˆj where Fx= 2 N, Fy=−4 N,sx= 6 m, and sy= 2 m.Find the work done by the force on the particle.Answer in units of J
(B)Find the angle between ~Fand ~s.
- Anonymous1 month ago
Take the dot product:
work = F • s = (2, -4)N • (6, 2)m = (2*6-4*2) N·m = 4 J