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# 35. The volume of 1.43 mol of gas at 63.0 kPa and 23.00 °C is ________ L.?

a. 4.34

b. 0.552

c. 55.9

d. 790

e. 0.351

### 3 Answers

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- SpacemanLv 71 month ago
Ideal Gas Law

n = number of moles of gas = 1.43 mol

P = pressure of gas = 63.0 kPa = 0.621747 atm

T = temperature of gas = 23.00 °C = 296.15 K

R = ideal gas constant = 0.082057 L atm / (mol K)

V = volume of gas = to be determined

PV = nRT

V = nRT/P

V = [(1.43 mol)(0.082057 L atm / (mol K))(293.15 K)] / 0.621747 atm

V = 55.89200782 L

Source(s): https://www.reference.com/science/pv-nrt-units-a28... https://www.digitaldutch.com/unitconverter/tempera... https://www.digitaldutch.com/unitconverter/pressur...- Login to reply the answers

- Anonymous1 month ago
Ideal gas equation, PV=nRT. If you understand this (obviously you don't), you don't even need a calculator with those choices, the correct one is obvious. Be sure to convert deg C to K for gas problems.

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- 1 month ago
Hi my name is officer uncircumcised

- pisgahchemistLv 71 month agoReport
Is your nickname Dick?

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