35. The volume of 1.43 mol of gas at 63.0 kPa and 23.00 °C is ________ L.?
- SpacemanLv 71 month ago
Ideal Gas Law
n = number of moles of gas = 1.43 mol
P = pressure of gas = 63.0 kPa = 0.621747 atm
T = temperature of gas = 23.00 °C = 296.15 K
R = ideal gas constant = 0.082057 L atm / (mol K)
V = volume of gas = to be determined
PV = nRT
V = nRT/P
V = [(1.43 mol)(0.082057 L atm / (mol K))(293.15 K)] / 0.621747 atm
V = 55.89200782 LSource(s): https://www.reference.com/science/pv-nrt-units-a28... https://www.digitaldutch.com/unitconverter/tempera... https://www.digitaldutch.com/unitconverter/pressur...
- Anonymous1 month ago
Ideal gas equation, PV=nRT. If you understand this (obviously you don't), you don't even need a calculator with those choices, the correct one is obvious. Be sure to convert deg C to K for gas problems.
- 1 month ago
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