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A(n) 69.8 kg astronaut becomes separated

from the shuttle, while on a space walk. She

finds herself 61 m away from the shuttle and

moving with zero speed relative to the shuttle.

She has a(n) 0.722 kg camera in her hand

and decides to get back to the shuttle by

throwing the camera at a speed of 12 m/s in

the direction away from the shuttle.

How long will it take for her to reach the

shuttle? Answer in minutes.

1 Answer

  • Anonymous
    1 month ago

    Conservation of momentum shall apply :

    Va = Vc*mc/ma = 12*0.722/69.8 = 0.124 m/sec

    time t = d/V = 61/(0.124*60) = 8.20 min

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