cant find the answer ?
A(n) 69.8 kg astronaut becomes separated
from the shuttle, while on a space walk. She
finds herself 61 m away from the shuttle and
moving with zero speed relative to the shuttle.
She has a(n) 0.722 kg camera in her hand
and decides to get back to the shuttle by
throwing the camera at a speed of 12 m/s in
the direction away from the shuttle.
How long will it take for her to reach the
shuttle? Answer in minutes.
- Anonymous1 month ago
Conservation of momentum shall apply :
Va = Vc*mc/ma = 12*0.722/69.8 = 0.124 m/sec
time t = d/V = 61/(0.124*60) = 8.20 min