A jet airliner moving initially at 148 mph(with respect to the ground)...?
A jet airliner moving initially at 148 mph(with respect to the ground) to the east moves into a region where the wind is blowing at 445 mph in a direction 77◦ north of east.What is the new speed of the aircraft with respect to the ground? Answer in units of mph.
- Anonymous2 months agoFavorite Answer
if wind speed 445 mph (which is a nonsense)
Vx = 148+445*cos 77 = 248 mph
Vy = 445*sin 77 = 434 mph
V = √Vx^2+Vy^2 = 500 mph
- Andrew SmithLv 72 months ago
Very slow jet aircraft and very strong wind.
These form a triangle with an angle of 103 at the vertex.
c= sqrt( a^2 + b^2 -2ab cos( theta))= sqrt( 148^2+445^2-2*148*445*cos(103) ) =500mph