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# A jet airliner moving initially at 148 mph(with respect to the ground)...?

A jet airliner moving initially at 148 mph(with respect to the ground) to the east moves into a region where the wind is blowing at 445 mph in a direction 77◦ north of east.What is the new speed of the aircraft with respect to the ground? Answer in units of mph.

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- Anonymous2 months agoFavorite Answer
if wind speed 445 mph (which is a nonsense)

Vx = 148+445*cos 77 = 248 mph

Vy = 445*sin 77 = 434 mph

V = √Vx^2+Vy^2 = 500 mph

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- Andrew SmithLv 72 months ago
Very slow jet aircraft and very strong wind.

These form a triangle with an angle of 103 at the vertex.

c= sqrt( a^2 + b^2 -2ab cos( theta))= sqrt( 148^2+445^2-2*148*445*cos(103) ) =500mph

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