If 5.50 mol of HCl and 3.00 mol of O2 react according to the following equation, how many grams of water will form? 4HCl+O2=2H20+2Cl2?
- GTBLv 72 months ago
5.50/2 moles water formed
- Roger the MoleLv 72 months ago
4 HCl + O2 → 2 H2O + 2 Cl2
5.50 moles of HCl would react completely with 5.50 x (1/4) = 1.375 moles of O2, but there is more O2 present than that, so O2 is in excess and HCl is the limiting reactant.
(5.50 mol HCl) x (2 mol H2O / 4 mol HCl) x (18.01532 g/mol) = 49.5 g H2O
- davidLv 72 months ago
This is a limiting reatant problem
the bal. eq. gives you a mole ratio of 4/1 .. so it should be obvious that HCl is the limiting reactant
5.50 X 2/4 = 2.75 mole H2O will be formed
... now use the molar mass to change this to grams
... molar mass H2O = 2.00 + 16.00 = 18.00
18.00 X 2.75 = ____ grams >>> just use your calculator for the final answer