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# Is it possible for a black hole to have its schwarzschild radius less than its actual radius?

### 8 Answers

- martinLv 72 months agoFavorite Answer
Yes. Photographs of black holes seem to show two different boundaries, like a circle within a bigger circle.

- 2 months ago
In that case, it wouldn't be a black hole. It would be a star or planet. The definition of a black hole is a body whose entire mass squeezes inside its Schwartzchild radius.

By the way, the actual radius of any black hole is zero. All the mass is at a point.

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- daniel gLv 72 months ago
No and the reason is the extreme density of the mass. You need to read more:

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- Ronald 7Lv 72 months ago
Yes

Because it is the last point before the Singularity

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- 2 months ago
No... the definition of the Schwarzschild Radius is the point on or out from a mass where the escape velocity equals the speed of light... and, that's *also* where the Event Horizon of a black hole is - so, the Schwarzschild Radius can't be less...

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- MorningfoxLv 72 months ago
What does "actual radius" mean to you? If you're thinking about some solid surface, like a planet or neutron star, then the answer is no. The thing at the center of a black hole is much smaller than the Schwarzschild radius, even for a rotating BH.

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Ditto what the other person said. You are confusing the event horizon at the Schwarzchild radius as the black hole, the singularity that is surrounded by the event horizon, surrounded by an accretion disc