Anonymous
Anonymous asked in Science & MathematicsAstronomy & Space · 2 months ago

Is it possible for a black hole to have its schwarzschild radius less than its actual radius?

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  • martin
    Lv 7
    2 months ago
    Favorite Answer

    Yes. Photographs of black holes seem to show two different boundaries, like a circle within a bigger circle.

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    • CarolOklaNola
      Lv 7
      2 months agoReport

      Ditto what the other person said. You are confusing the event horizon at the Schwarzchild radius as the black hole, the singularity that is surrounded by the event horizon, surrounded by an accretion disc 

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  • 2 months ago

    In that case, it wouldn't be a black hole. It would be a star or planet. The definition of a black hole is a body whose entire mass squeezes inside its Schwartzchild radius.

    By the way, the actual radius of any black hole is zero. All the mass is at a point.

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  • 2 months ago

    No and the reason is the extreme density of the mass. You need to read more:

    https://en.wikipedia.org/wiki/Schwarzschild_radius

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  • 2 months ago

    Yes

    Because it is the last point before the Singularity

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  • 2 months ago

    No... the definition of the Schwarzschild Radius is the point on or out from a mass where the escape velocity equals the speed of light... and, that's *also* where the Event Horizon of a black hole is - so, the Schwarzschild Radius can't be less...

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  • 2 months ago

    What does "actual radius" mean to you? If you're thinking about some solid surface, like a planet or neutron star, then the answer is no. The thing at the center of a black hole is much smaller than the Schwarzschild radius, even for a rotating BH.

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  • Mark
    Lv 7
    2 months ago

    No, it isn't.  That even holds for "mini-black holes".

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  • Dze
    Lv 7
    2 months ago

    dont under-estimate the power of the schwarz ...

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