electric circuit question?
I do not have any idea to solve this question. Can you solve this?
- oldschoolLv 72 months ago
ω = 4000 rad/s
-j/(4000*20e-6) = -j12.5 for capacitor.
j*4000*15e-3 = j60 for the inductor
v(t) = [0.120*(-j12.5)/(40 - j12.5 + j60)]*40Ω
v(t) = [0.120*(-j12.5)/(40 + j47.5)]*40Ω
Convert to polar form
v(t) = 0.966 /_-139.9° <<<<<