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# A woman of mass 45 kg jumps off the bow of an 80 kg canoe that is initially at rest.?

If her velocity is 3.5 m/s to the right, what

is the velocity of the canoe after she jumps?

Answer in units of m/sˆı.

### 3 Answers

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- MyRankLv 61 month ago
Given,

Mass of woman (m₁) = 45kg

Mass of canoe (m₂) = 80kg

Velocity of woman (v₁) = 3.5m/sec

Velocity of canoe (v₂) = ?

Using conservation of momentum:-

m₁v₁ = m₂v₂

= v₂ = m₁v₁/m₂ = 45kg x 3.5m/sec / 80kg

= 1.968m/sec ≈ 1.97m/sec

∴ velocity of canoe (v₁) = 1.97m/sec.

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- VamanLv 72 months ago
Balance the momentum.

45*3.5=80 v.

v=45*3.5/80=1.97 m/s

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- Anonymous2 months ago
Conservation of momentum.

Mass * speed = mass * speed.

Simple calc.

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