Physics help required ?
A projectile starts from rest and moves 4.8 m
down a frictionless ramp inclined at 14◦ with
The acceleration of gravity is 9.8 m/s ^2
With what speed will it leave the ramp?
Answer in units of m/s.
What will be the range of the projectile if
the bottom of the ramp is 2.2 m above the
Answer in units of m.
- WhomeLv 71 month agoFavorite Answer
v = √(2(-9.8)(4.8sin-14) = 4.77 m/s
-2.2 = 0 + (4.77sin-14)t + ½(-9.8)t²
0 = 4.9t² + 1.15t - 2.2
quadratic formula or other means gives a positive answer of
t = 0.56 s
r = (4.77cos-14)(0.56) = 2.6 m