A 2400 kg car travels to the north is slowed down from an initial velocity of 36.5 m/s by a 6800 N braking force acting opposite cars motion?

A 2400 kg car traveling to the north is slowed down uniformly from an initial velocity of 36.5 m/s by a 6800 N braking force acting opposite the car’s motion.

a) What is the car’s velocity after 1.52 s? Answer in units of m/s.

b) How far does the car move during the 1.52 s s? Answer in units of m.

c) How long does it take the car to come to a complete stop?  Answer. in units of s.

1 Answer

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  • Whome
    Lv 7
    2 months ago
    Favorite Answer

    a = 6800 / 2400 = 2.83 m/s²

    a) v = 36.5 - 2.83(1.52) = 32.2 m/s

    b) d = 36.5(1.52) - ½(2.83)(1.52²) = 52.2 m

    c) t = 36.5 / 2.83 = 12.9 s

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