A 2400 kg car travels to the north is slowed down from an initial velocity of 36.5 m/s by a 6800 N braking force acting opposite cars motion?
A 2400 kg car traveling to the north is slowed down uniformly from an initial velocity of 36.5 m/s by a 6800 N braking force acting opposite the car’s motion.
a) What is the car’s velocity after 1.52 s? Answer in units of m/s.
b) How far does the car move during the 1.52 s s? Answer in units of m.
c) How long does it take the car to come to a complete stop? Answer. in units of s.
- WhomeLv 72 months agoFavorite Answer
a = 6800 / 2400 = 2.83 m/s²
a) v = 36.5 - 2.83(1.52) = 32.2 m/s
b) d = 36.5(1.52) - ½(2.83)(1.52²) = 52.2 m
c) t = 36.5 / 2.83 = 12.9 s