I need to do this for homework but i dont even know how to do this question:
A person situated in a valley, exactly in the middle two mountains, screams;
at 4.0s it echoes back to him
at 4.6s it echoes back to him a second time
Calculate the distance between the two mountains knowing the speed of sound is 340m/s.
What formula do I even use for this?
- VamanLv 72 months agoFavorite Answer
Let him be in the middle. The distance be x to one mountain and x+h to the second mountain. He will hear echo after 2x/v=4 time. The second time it will be 2 (x+h)/v=4.6. The distance between mountain will be 2x+h.
x+h=v*2.3, x=2*v, 2x+h= 4.3 v, Put the value of the sound velocity.
4.3*340=1462 m is the distance between mountains.
- PhilomelLv 72 months ago
If this is the exact wording of the question, There is no answer because there is no question. You cannot answer statements of facts. This is a puzzle. If he is situated exactly in the middle (given), How can the times be unequal? There may be a very heavy fog bank on one side or there may be a hotel on one side
- Anonymous2 months ago
< facepalm >
- Andrew SmithLv 72 months ago
If your teacher asks you to do homework about something that you were not given enough background then challenge that teacher. I bet that is not the case however. The sound has echoed several times before 4 seconds. It has echoed just ONCE more at 4.6 seconds
So it has got to the mountain and back again in 0.6 seconds.
The distance to the mountain and back again is 0.6 * 340 m And this is ALSO the distance between the two mountains ( because he is in the exact middle.)
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- RealProLv 72 months ago
The first time he hears the sound bouncing back from one side of the valley and the second time from the other side of the valley. There are infinite back and forths but these two are the first ones to be heard and the loudest.
340*(4.0/2 + 4.6/2) m = ?