There r 8.8liters ofgas in a piston at pressure of 1.75atmospheres Whats the newpressure in atmospheres inside piston? full question details?

full question>>> There are 8.8 liters of gas in a piston at a pressure of 1.75 atmospheres. The temperature remains constant, and the gas is compressed to a volume of 6.2 liters. What is the new pressure, in atmospheres, inside the piston?

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    P * V = n * R * T

    Since n, R, and T are kept constant, then we can set it all equal to some constant k

    P * V = k

    P[1] * V[1] = k

    P[2] * V[2] = k

    P[1] * V[1] = P[2] * V[2]

    P[1] = 1.75 atm

    V[1] = 8.8 liters

    V[2] = 6.2 liters

    P[2] = ?

    1.75 atm * 8.8 liters = P atm * 6.2 liters

    1.75 * 8.8 / 6.2 = P

    1.75 * 88/62 = P

    P = (7/4) * (88/62)

    P = 7 * 88 / (4 * 62)

    P = 7 * 8 * 11 / (4 * 2 * 31)

    P = 7 * 11 / 31

    P = 77 / 31

    P = ‭2.4838709677419354838709677419355‬

    Take it to 3 sf

    2.48 atm

    To 2 sf

    2.5 atm

  • Anonymous
    9 months ago

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