sulfur hexafluoride gas occupies 9.92 L at 294°C. what temperature (in °C) is needed to reduce the volume to 1.37 L? significant figures.?
- Roger the MoleLv 73 weeks ago
(294 + 273) K x (1.37 L / 9.92 L) = 78.305 K = -195°C
- Anonymous3 weeks ago
1.37 L / 9.92 L * (294 + 273.15) = new temperature. Assuming ideal gas behavior which is likely not a good assumption in this case.
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