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# Comparing the waves y1=A*e^(i(k+b)x) y2=B*e^(i(kx+a)), the difference in wavelength for the two waves will depend on b right?

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- Steve4PhysicsLv 73 weeks ago
The real coefficient1in front of the 'x' equals 2π/λ.

For example if we have e^(24ix) then

24 = 2π/λ

λ = 2π/24 = π/12

In e^(i(k+b)x) this coefficient is (k+b) giving:

k+b = 2π/λ

λ = 2π/(k+b)

In e^(i(kx+a)) this coefficient is k giving:

k = 2π/λ

λ = 2π/k

So the difference in wavelengths is:

Δλ = 2π/k – 2π/(k+b)

= 2π(1/k – 1/(k+b))

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