# Trig help - right triangles?

Find the value of x of the right triangle.

The base leg is x+3

The hypotenuse is the square root of 117.

### 3 Answers

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- KrishnamurthyLv 72 weeks ago
Find the value of x of the right triangle.

The base leg is x+3

The hypotenuse is the square root of 117.

x^2 + (x + 3)^2 = 117

2x^2 + 6x - 108 = 0

x^2 + 3x - 54 = 0

x^2 + 9x - 6x - 54 = 0

x(x + 9) - 6(x + 9) = 0

(x - 6)(x + 9) = 0

The value of x of the right triangle is 6.

- SpacemanLv 72 weeks ago
x² + (x +3)² = 117

x² + x² +6x + 9 = 117

2x² + 6x + 9 = 117

2x² + 6x - 108 = 0

2x²/2 + 6x/2 - 108/2 = 0

x² + 3x - 54 = 0

(x + 9)(x - 6) = 0

x + 9 = 0

x = -9

x - 6 = 0

x = 6 ANSWER

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