an object of volume 0.0882 m^3 is immersed in a fluid; it experiences a buoyant force of 671 N. What is the density of the fluid?

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  • MyRank
    Lv 6
    3 weeks ago

    Given,

    Volume (V) = 0.0882m³Force (F) = 671NDensity (ρ) = ?Acceleration due to gravity (g) = 9.81m/sec²We know that:-Density (ρ) = mass (m) / volume (v) = (force (F) / g) / volume (v) ∵ F=mg= (671N/9.81m/sec²) / 0.0882m³= 775.5kg/m³ ≈ 776kg/m³.

  • 4 weeks ago

    The "buoyant force" is the weight of the fluid displaced or moved out of the way = mass of fluid * g. = 671N

    So mass of fluid = 671/9.8 = 68.5kg. Now we know the mass and the volume is given so Density = Mass/Volume

    Density = 68.5/0.0882 = 776kg/m³

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