chlorine a yellow gas can be produced by mixing vinegar and bleach. what volume is occupied by 181.0 g of chlorine at 60.0 C and 96.0 kPa?

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  • 3 weeks ago

    The gas is chlorine, Cl₂.

    Pressure, P = 96.0 kPa

    Volume, V = ? L

    Molar mass = 35.5 × 2 g/mol = 71.0 g/mol

    No. of moles, n = 181.0/71.0 mol

    Gas constant, R = 8.314 L kPa / (mol K)

    Temperature, T = (273.2 + 60.0) K = 333.2 K

    Gas law: PV = nRT

    Then, V = nRT/P

    Volume, V = (181.0/71.0) × 8.314 × 333.2 / 96.0 L = 73.6 L

  • Anonymous
    3 weeks ago

    How many moles of Cl2 do you have?  (around 2)

    then use the ideal gas equation, PV=nRT.  About 55 L

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