Help with Chem 20 problem?

A sample of nitrogen gas at -25.0 C and 92.0 kPa occupies a volume of 13.0 L. How many moles of nitrogen is in the sample? Include units in your answer.

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  • Ash
    Lv 7
    3 weeks ago
    Favorite Answer

    n = PV/RT = (92.0 kPa)*(13.0 L) / [(8.31 L kPa / K mol)*((-25.0 °C + 273) K)

    = 0.580 moles

  • 3 weeks ago

    PV=nRT -> Ideal gas law

    P = 92kPa

    V=13 L

    n= ?

    R = 8.314472( L*kPa/K*mol) - Constant 

    T = -25C + 273.15 = 248.15K

    (92kPa)(13L) = n(8.314472)(248.15K)

    = 0.5797mols ---> 0.58 mols (2 sig digits)

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