How much work must you do to push a 13 kg block of steel across a steel table (μk=0.6) at a steady speed of 1.1 m/s for 8.0 s ?

How much work must you do to push a 13 kg block of steel across a steel table (μk=0.6) at a steady speed of 1.1 m/s for 8.0 s?

b.)What is your power output while doing so?

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  • 3 weeks ago
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    Normal force = weight = mg

    Friction = µmg

    If constant speed then push force = friction

    Work = µmg * (1.1 m/s) * (8.0 s)

    Round your answer to 2 significant digits and not 3.

    Power = work / time. So that's speed * force.

    1.1 * 0.6 * 13 * 9.8 watts

  • Anonymous
    3 weeks ago

    you need to do your own pearson homework.

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