# Decomposition of hydrogen peroxide, percentage yield of oxygen is 93%. What is the actual yield gm of oxy if you start with 100. g H2O2? ?

2H2O2→ 2H2O + O2.

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- Roger the MoleLv 73 weeks agoFavorite Answer
(100. g H2O2) / (34.015 g H2O2/mol) x (1 mol O2 / 2 mol H2O2) x (0.93) x (31.99886 g O2/mol) = 43.7 g O2

- billrussell42Lv 73 weeks ago
Hydrogen Peroxide ➜ Water + Oxygen

2H₂O₂ ➜ 2H₂O + O₂

2 moles of H₂O₂ ➜ 2 moles of water + 1 mole of O₂

68 g of H₂O₂ ➜ 36 g of water + 32 g of O₂

Assuming that "93%" means 93% of theoretical yield

given the 93% number, 68 g of H₂O₂ would yield 0.93•32 g of O₂, or 29.76 g

so the ratio is 29.76/68

and x/100 = 29.76/68

x = 51.3 g

OR assuming that "93%" means 93% actual yield, then answer is 93 g

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