Anonymous
Anonymous asked in Science & MathematicsPhysics · 3 weeks ago

Physics help?

A man weighs 746 N on the surface of the Earth. What would the force of gravity be on the man if he were placed at a point in space that was 7 times as far away from the center of the Earth as he was when he stood on the surface?

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  • 3 weeks ago
    Favorite Answer

    The value of 'g' obeys the inverse square law.  So being 7 times further away reduces g (and hence weight ) by a factor 7² = 49.  New weight = 746/49 = 15.2N

  • oubaas
    Lv 7
    3 weeks ago

    Ws = We/7^2 = 746/49 = 15.2 N

  • 3 weeks ago

    The weight of an object is equal to the Universal gravitational force.

    m * g = G * M * m ÷ d^2

    g = G * M ÷ d^2

    As you look at this equation, you can see that the value of the gravitational acceleration is inversely proportional to the square of the distance from the center of the earth.

    a = 9.8 ÷ 7^2 = 0.2

    Weight = 0.2 * 746 = 149.2 kg

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