A man weighs 746 N on the surface of the Earth. What would the force of gravity be on the man if he were placed at a point in space that was 7 times as far away from the center of the Earth as he was when he stood on the surface?
- Steve4PhysicsLv 73 weeks agoFavorite Answer
The value of 'g' obeys the inverse square law. So being 7 times further away reduces g (and hence weight ) by a factor 7² = 49. New weight = 746/49 = 15.2N
- oubaasLv 73 weeks ago
Ws = We/7^2 = 746/49 = 15.2 N
- electron1Lv 73 weeks ago
The weight of an object is equal to the Universal gravitational force.
m * g = G * M * m ÷ d^2
g = G * M ÷ d^2
As you look at this equation, you can see that the value of the gravitational acceleration is inversely proportional to the square of the distance from the center of the earth.
a = 9.8 ÷ 7^2 = 0.2
Weight = 0.2 * 746 = 149.2 kg