chem help please?

for the balanced equation shown below, if the reaction of 0.112 grams of H2 produces 0.745 grams of h2o                                     fe3o4+ 4h2   3fe+ 4h20

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  • 3 weeks ago

    Fe3O4 + 4 H2 = 3 Fe + 4 H2O

    moles of H2 = 0.112 grams / 2.01588 g/ mol = 0.0556 moles of H2

    from the equation the theoretical moles of H2O = 0.0556 moles of H2O

    mass of these moles = 0.0556 moles * 18.01528 g / mol = 1.001 g

    but we have 0.745 grams

    % yield = 0.745 grams / 1.001 g *100 = 74.4 %

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