Related Rate, Volume of cube?

V = s^(3)

s(t) = t

Then s'(t) = 1 and V'(t) = 3t^(2)

Now let V(t) = t

Then V'(t) = 1

And s'(t) = ?

Why is s'(t) = (1 / (3t^(2/3))?

Update:

s being a side length of a cube

Update 2:

The closest I get is:

If we can write V = s^(3) = t

dV/dt = 3s^(2)*ds/dt = 1

ds/dt = 1 / 3s^(2)

What am I missing?

There are no answers yet.
Be the first to answer this question.