Anonymous
Anonymous asked in Science & MathematicsMathematics · 4 weeks ago

The following absolute value inequality is an "OR" situation? True or False?

|17x +2| greater than or equal to 12

I put False? am i wrong?

3 Answers

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  • JOHN
    Lv 7
    4 weeks ago

    Yes, the logical scheme here is ‘P or Q’ is a true proposition if either P is true or Q is true. In formal logic ‘P or Q’ = T if either P = T or Q = T or P = T & Q = T. Here the last is not applicable because |17x + 2| = 12 precludes |17x + 12|> 12. We must have exactly one of a < b or a = b or a > b being true. If one is asked to prove that |17x + 12|> 12 and you’ve managed to prove that |17x + 12| ≥ 12, you have more work to do to exclude |17x + 12| = 12. |17x + 12|> 12 is sharper than |17x + 12| ≥ 12.

  • david
    Lv 7
    4 weeks ago

    |17x +2| greater than or equal to 12

      case 1 --  17x +2 greater than or equal to 12                  17x  greater than or equal to 10

                        x greater than or equal to 10/17

      case 2 --  17x +2 less than or equal to -12

                      17x  less than or equal to -14 

                        x  less than or equal to -14 /17

      solution  does not use the interval from  -14/17 thru 10/17   ....  it includes the ends of the x line ...   so YES this is an "or"

  • alex
    Lv 7
    4 weeks ago

    |17x +2| ≥ 12 is an "OR" 

    --->TRUE

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