Calculate the pH of the cathode compartment solution if the cell emf at 298 K is measured to be 0.680V when [Zn2+]= 0.20 M and PH2= 0.96 atm?
- 冷眼旁觀Lv 63 weeks agoFavorite Answer
Anodic half reaction: Zn(s) → Zn²⁺(aq) + 2e⁻ …. E° = 0.76 V
Cathodic half reaction: 2H⁺(aq) + 2e⁻ → H₂(g) …. E° = 0 V
Overall reaction: Zn(s) + 2H⁺(aq) → Zn²⁺(aq) + H₂(g)
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