What are two integers whose sum is 5 and product is -66?

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  • Como
    Lv 7
    3 weeks ago

    :-

    Let integers be x and y

    x  + y   = 5

    x y   = - 66

    x ( 5  - x )  = - 66

    5x  - x²   = - 66

    x²  - 5 x  + 66   = 0

    ( x  - 11 ) ( x  + 6 )   = 0

    x   = 11 , x   = - 6

    Integers are 6 , - 11

  • 3 weeks ago

    11 & -6................

  • 3 weeks ago

    11 and -6 are the two integers whose sum is 5 and product is -66.

  • sepia
    Lv 7
    3 weeks ago

    Two integers whose sum is 5 and product is -66: 11 and -6

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  • 3 weeks ago

    if the sum of the two integers, a and b, is 5:

    a + b = 5

    and if the product of the two integers is -66:

    a * b = -66

    we can find a in terms of b and plug it back into another equation:

    a + b = 5

    a = 5 - b

    If a = b - 5 in this equation, we have to assume it is true in the other one to find the values that satisfy the system, therefore:

    a * b = -66

    (5 - b) * b = -66

    -b^2 + 5b + 66 = 0

    b^2 - 5b - 66 = 0

    (b - 11) (b + 6) = 0

    your two numbers will be -6 and 11

  • 3 weeks ago

    x + y = 5

    xy = -66

    Solve the system of equations.

    x = -11, y = 6

  • A.J.
    Lv 7
    3 weeks ago

    A+B=5  >>> B=5-A  

    AB= -66

    A(5-A)=-66

    5A - A² = -66

    0 = A² - 5A -66

    0 = (A+6)(A-11)

    A= -6, 11 and B= 11, -6  by the pairing

    Product is -66 and sum is +5 so -6 and +11 are the two numbers

  • 3 weeks ago

    x+y=5

    xy=-66

    So

    x=5-y  and y=(-66/x)

    x=(5x+66)/x

    x²=5x+66

    x²-5x-66=0

    x=-6 so y=11

    x=11 so y=-6

  • 3 weeks ago

    x+y = 5

    xy = –66

    y = 5 – x

    x(5–x) = –66

    5x – x² = –66

    x² – 5x – 66 = 0

    (x + 6)(x – 11) = 0

    x = 11, –6

    y = –6, 11

  • 3 weeks ago

    -6 and 11

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