Ash asked in Science & MathematicsPhysics · 3 weeks ago

what is the required length of a 4 inch wedge if it is engineered to deliver a force six times greater than the effort?

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  • oubaas
    Lv 7
    3 weeks ago

    disregarding friction :

    F*L = h*m*g

    L = h*(m*g) / F

    if m*g/F = 6 , then

    L = h*6F/F = 6h = 24''

  • 3 weeks ago

    Friction is substantial when using a sliding wedge. This makes the question impossible.

    If you somehow had a frictionless wedge that was 4 " thick and 6*4 = 24 " long then the expansion force would be six times greater than the longitudinal insertion force.

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