Help needed, I've read all the material but I still don't know how to answer these questions.
- NCSLv 77 months agoFavorite Answer
The second graph looks wonky, and there is a lot you haven't told us. For instance: is the length along the bottom the total length of the spring, or just the amount of stretch?
Looking at the first graph, the slope F / x gives the spring constant k. The bottom corner appears to be (x, F) = (0.45m, 1.3N) and the top right corner appears to be (x, F) = (1.18m, 4.9N). Then
k = (4.9-1.3)N / (1.18-0.45)m = 4.93 N/m
From this we can find the length of the elastic band (which I think is important):
F = kΔx
and using the top right point again,
4.9 N = 4.93N/m * Δx
Δx = 0.994 m
which suggests to me that the "spring" is
1.18m - 0.99m = 0.19 m long
So, for that point,
Eelastic = ½k(Δx)² = ½*4.93N/m*(0.99m)² = 2.435 J
and you are supposed to "prove" that this is equal to the change in GPE -- m*g*Δx.
But you haven't given us the mass, either.
Hopefully, this will get you moving along the path for solution. If so, please award Best Answer!