Use the ideal-diode model to analyze the circuit shown below.?
Which diode is on? Which one is off? Explain your reasoning.
- billrussell42Lv 72 months agoFavorite Answer
diode on the right, if the left circuit were missing, would put 3 volts across R2
diode on the left, if the right circuit were missing, would put 10(6)/(6+4) volts across R2, which is 6 volts.
so diode on the right would be cuttoff, as it is reverse biased, with 6 volts on the cathode and 3 volts on the anode. Diode on the left would be on, with 6 volts on the cathode and slightly above 6 volts on the anode.
- PhilomelLv 72 months ago
10v is impressed through R1, D1 and R2.
The current is 10/10K= 1mA. the voltage across R2= 1mA*6K = 6V, D2 is off with 6-3v= 3V across it. D1 is on. D1 will have zero across it because the diodes are ideal.