# Reindex the series to start at k=1?

∑∞k=10 (([k+2)(k+1)x^(k+1)])/k+3)=∑∞k=1 ...............

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∑∞k=10 (([k+2)(k+1)x^(k+1)])/k+3)=∑∞k=1 ...............

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Thanks

the solution is ((k+11)(k+10)x^(k+10))/(k+12)