If 5.7 kg of CO₂ are produced during a combustion reaction, how many molecules of CO₂ would be produced?

Question

show work please

Answer 1

Favorite Answer

1st find molar mass of CO2  --  1x12 + 2x16  =  44g/mole

next convert using the metric(SI) system and Avogadro's number

   (5.7 kg) X (1000g/kg) X (1mole/44g) X (6.022x10^23 molecule/mole)

  ....  now just use a calculator

  =  7.8 x 10^25 molecules

Answer 2

How many molecules ....

5.7 kg CO2 x (1000 g / 1 kg) x (1 mol CO2 / 44.0g CO2) x (6.022x10^23 molecules CO2 / 1 mol CO2) = 7.8x10^25 molecules CO2

Showing work means showing the setup for the unit-factor method where each conversion factor takes us from what is given to the answer we desire.  The units we don't want cancel out, leaving the units we do want.  That's why it is also called dimensional analysis.