# 5.60 m length of 1.8 mm -diameter wire carries a 770 mA current when 18.0 mV is applied to its ends. The drift velocity is 1.3×10−5 m/s?

Find resistance of the wire

Update:

Determine the electric field inside the wire and number of free electrons per unit volume

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- MyRankLv 64 weeks agoFavorite Answer
Given,

Current (I) = 770mn = 770 x 10⁻³A

Voltage (v) = 18mv = 18 x 10⁻³volts

Resistance (R) = ?

Diameter of wire (D) = 1.8 x 10⁻³m

Length of wire (L) = 5.60m

We know that:-

Voltage (v) = current (I) x resistance (R)

Resistance (R) = voltage (v) / current (I) = 18 x 10⁻³ / 770 x 10⁻³

= 0.023Ω

∴ Resistance (R) = 0.023Ω.

Source(s): https://myrank.co.in/ - NCSLv 71 month ago
resistance = potential / current

R = 18.0mV / 770mA = 0.0234 Ω

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