a gaseous mixture made of 6.00g of 02 and 9.00g of CH4 is placed in a vessel at 0c. what is the partial pressure of each gas and what is the total pressure in the vessel? the volume of vessel is 10.0l.
- az_lenderLv 74 weeks ago
That's 0.375 moles of O2 and 0.5625 moles of CH4.
p = nRT/V
= (0.9375 mol)(8.314 Pa*m^3/molK)(273.15 K)/(0.01 m^3)
= about 200 kPa but use a calculator.
Then the partial pressures can be found,
because the O2 exerts 6/15 = 2/5 of the pressure,
and the methane exerts 9/15 = 3/5 of the total pressure.