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Anonymous

# Solving Trig Equations?

Where did i go wrong

### 3 Answers

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- geezerLv 73 months ago
How are we supposed to know where you went wrong

if you don't tell us what you did to get the wrong answer ?

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- 3 months ago
You should probably show your work. Then we can guide you on where you went wrong.

10 * sec(x)^2 + 5 * tan(x)^2 - 15 = 0

10 * (1 + tan(x)^2) + 5 * tan(x)^2 - 15 = 0

10 + 10 * tan(x)^2 + 5 * tan(x)^2 - 15 = 0

15 * tan(x)^2 - 5 = 0

3 * tan(x)^2 - 1 = 0

tan(x)^2 = 1/3

tan(x) = +/- sqrt(3)/3

So where you went wrong is that you missed 2 answers. You only gave the values from 0 to pi, rather than from 0 to 2pi.

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- Anonymous3 months ago
how the hell is anyone supposed to know "where" you went wrong when you didnt provide all the work?????

well you obviously went wrong at the end by getting the wrong answer

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