Physics help?

Two men are pulling a boat down a canal by exerting forces on ropes attached to the boat. One man is on one side of the canal and the second man is on the other side of the canal. If the first man pulls with a force of 424 N at an angle of 60.0° to the canal, and the second man pulls with a force of 345 N at an angle of 30.0° to the canal, 

a) What is the component of the net force causing the boat to move down the canal? b) What is the minimum force a third man would need to exert to keep the boat moving straight down the canal?

2 Answers

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  • oubaas
    Lv 7
    3 months ago
    Favorite Answer

    F1y = 424*cos 60° = 424*0.5 = 212 N

    F1x = 424*sin 60° = 212√3 N ( ≅ 367 N)

    F2y = 345*cos 30° = 345/2*√3 N ( ≅ 299 N)

    F2x = -345*sin 30 = -345*0.5 = -173 N

    Component of the net force FN causing the boat to move down the canal:

    FNy = F1y+F2y = 212+299 = 511 N

    Minimum force Fx a third man would need to exert to keep the boat moving straight down the canal :

    Horizontal equilibrium requires F1x+F2x+Fx = 0

    Fx = -F1x-F2x = -367+173 = -194 N

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  • 3 months ago

    I doooont know t/tttttt

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