Gaby asked in Science & MathematicsPhysics · 4 weeks ago

In the combination of 3 Ω resistors shown in the diagram?

a) What is the resistance of each of the two parallel combinations?

b) What is the total equivalent resistance between points A and B?

c) If there is a voltage difference of 15 V between points A and B, what is the

current flowing through the entire combination?

d) What is the current flowing through each of the resistors in the three-resistor

parallel combination?

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2 Answers

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  • Whome
    Lv 7
    4 weeks ago

    Two parallel resistors

    Re = 1 / (1/3 + 1/3) = 1.5 Ω

    Three parallel resistors

    Re = 1 / (1/3 + 1/3 + 1/3) = 1.0 Ω

    Total equivelent resistance

    Re = 1.5 + 3 + 1.0 = 5.5 Ω

    Ι = 15 / 5.5 = 2.727272... = 2.7 Amps

    Through each of the three parallel resisters will be one third of the total

    I = 2.727 / 3 = 0.90909... = 0.91 Amps

  • 4 weeks ago

    Work out each parallel network first, then you have a simple three-value series network.

    From A to B:

    two 3R in parallel = 1.5R,

    then 3R,

    then three 3R in parallel = 1R.

    1.5 + 3 + 1 = 5.5R

    Current at 15V = 15 / 5.5 = 2.727272' Amps.

    With three equal resistors in parallel, the current is divided equally in three so that value divided by three.

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