An explosion released 1,000 kilograms of cesium137 into the atmosphere. If the half-life of 137Cs is 30.17 years, what is it in 130 years?

2 Answers

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  • 3 weeks ago

    1000 * (1/2)^(130/30.17) =~ 50.45299970396245456154554570699

  • Bryce
    Lv 7
    4 weeks ago

    0.5= e^(30.17k)

    ln0.5= 30.17k

    k= ln0.5/ 30.17

    A= 1000e(130*ln0.5/ 30.17)≈ 50.45 kg

    • Bryce
      Lv 7
      3 weeks agoReport

      Base e is frequently used in exponential and half-life problems.

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