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# Given the equation: 2KClO3 (s) --> 2KCl (s) + 3O2 (g) A 3.00-g sample of KClO3 is decomposed and the oxygen at 24.0°C and 0.977 atm is...?

Given the equation:

2KClO3 (s) --> 2KCl (s) + 3O2 (g)

A 3.00-g sample of KClO3 is decomposed and the oxygen at 24.0°C and 0.977 atm is collected. What volume of oxygen gas will be collected assuming 100% yield?

A.6.11×102 mL

B.4.07×102 mL

C.7.40×101 mL

D.9.16×102 mL

E.none of these

### 1 Answer

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- pisgahchemistLv 74 weeks ago
Volume of oxygen ....

Solve in two steps. (1) stoichiometry to find the moles of O2, (2) ideal gas equation to find the volume since the conditions are not at STP

2KClO3(s) --> 2KCl(s) + 3O2(g)

3.00g ................ ............. ? mol

3.00g KClO3 x (1 mol KClO3 / 122.55g KClO3) x (3 mol O2 / 2 mol KClO3) = 0.03672 mol O2 ............ to one extra "guard digit."

PV = nRT

V = nRT / P

V = 0.03672 mol x 0.08206 Latm/molK x 297K / 0.977 atm

V = 0.916L or 916 mL

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