Write a assembly program that increments by 2 the content of a register 10 times?
8 bit with two operands with the result stored in one of the input registers. if this helps
1)Write a program that adds two operands.
2)Write a program that adds operands until the new value to be added is 0.
3)Write a program that increments by 2 the content of a register 10 times.
4)Write a program that shifts the content of a register until the least significant bit is 0. stop shifting if the content of the register is 11111111
- husoskiLv 74 weeks ago
It's a single instruction on most CPUs:
addi R3,20 ; Add 20 to register R3
Of course, the opcode and register names are made up because you haven't specified what processor you're using. Every processor family has its own instruction set.
If you need to write a loop, that can be even more processor-specific. For example, 8086 code to increment register AX might look like:
mov cx,10 ; loop count
L1: inc ax ; increment AX by 2
loop L1 ; repeat a total of 10 times
The same idea on IBM S/390 might be:
L R0,=F'10' LOOP COUNT
L1 A R1,=F'2' INCREMENT R1 BY 2
BCT R0,L1 REPEAT A TOTAL OF 10 TIMES
- dewcoonsLv 74 weeks ago
Using what assembly language? As humans, we do not "write" in "assembly". It is a series of 0's and 1's. We use different languages to write the code and then compile it. Different processors uses different programs. Not enough information to answer the question.
- 4 weeks ago
May be or may be not