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Factor 64 - 9y^2

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  • 4 weeks ago

    Factor 64 - 9y^2

    8 ² - (3y)²

    (8 - 3y ) ( 8 + 3y )

  • 4 weeks ago

    64 - 9y²

    = 8² - (3y)²

    = 8² + 0 - (3y)²

    = 8² + (8×3y - 8×3y) - (3y)²

    = 8² + 24y - 24y - (3y)²

    = 8(8 + 3y) - 3y(8 + 3y)

    = (8 - 3y)(8 + 3y)

  • 4 weeks ago

    the answer to your question is(y-2.667)(y+2.667) 😜😌

  • 4 weeks ago

    factor  -9y^2+64

    -(9y^2-64)

    -(3y-8)(3y+8)

    (-3y+8)(3y+8)

    WolframAlpha

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  • Como
    Lv 7
    4 weeks ago

    -

    ( 8 - 3y ) ( 8 + 3y ) = 64 + 24y - 24y - 9y² = 64 - 9y²

  • oubaas
    Lv 7
    4 weeks ago

    it is the difference of 2 squares ( 64 = 8^2 ; 9y^2 = (3y)^2 ) ...and you are supposed to know that a^2-b^2 = (a+b)*(a-b)...therefore :

    64 - 9y^2 = (8+3y)*(8-3y)

  • sepia
    Lv 7
    4 weeks ago

    64 - 9y^2

    = (3y + 8)(8 - 3y)

  • 4 weeks ago

    a^2 - b^2 = (a - b)(a + b) =>

    64 - 9y^2 = (8 - 3y)(8 + 3y)

  • David
    Lv 4
    4 weeks ago

    This is a standard factorisation rule that can be useful to remember, the difference of two squares:

    a² - b² = (a + b)(a - b).

    If you multiply out the bracket, the cross terms cancel.

    So if you have something of the form ax² - b for some constants a and b, you know that you can factor them into

    ax² - b = (√ax + √b)(√ax - √b)

    In this case, both factors are perfect squares, so it works particularly nicely:

    64 - 9y² = (8 + 3y)(8 - 3y)

  • 4 weeks ago

    Learn to recognize the difference of squares and how to factor it:

    a² - b² = (a + b)(a - b)

    In your case:

    a² = 64

    b² = 9y²

    So:

    a = 8

    b = 3y

    Answer:

    (8 + 3y)(8 - 3y)

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