What is the molarity of an aqueous phosphoric acid solution if 12.55 mL is completely neutralized by 25.62 mL of 0.1232 M NaOH?

What is the equation  balanced? 

My answer was 0.1676

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  • 4 weeks ago

    H3PO4 + 3 NaOH → 3 H2O + Na3PO4

    (25.62 mL) x (0.1232 M NaOH) x (1 mol H3PO4 / 3 mol NaOH) / (12.55 mL H3PO4) =

    0.08383 M H3PO4

    [If you don't have the balanced equation you can't answer the question. Don't waste your time trying.]

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