Heat Calculation problem..help please?
Calculate the heat involved with 196 g KBr (MW = 119 g/mol) in the following reaction:
2KBr + H2SO4 + 120 kJ → K2SO4 + 2HBr.
- AshLv 71 month ago
moles of KBr involved = 196 g / (119 g/mol) = 1.65 mol
heat involved in reaction = (estimated heat involved from balanced equation/ moles of KBr from baanced eqution) x moles of KBr involved in the reaction
heat involved in reaction = (120 kJ / 2 mol) x (1.65 mol) = 99 kJ