Heat Calculation problem..help please?

Calculate the heat involved with 196 g KBr (MW = 119 g/mol) in the following reaction:

2KBr + H2SO4 + 120 kJ → K2SO4 + 2HBr.

1 Answer

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  • Ash
    Lv 7
    1 month ago

    moles of KBr involved = 196 g / (119 g/mol) = 1.65 mol

    heat involved in reaction = (estimated heat involved from balanced equation/ moles of KBr from baanced eqution) x moles of KBr involved in the reaction

    heat involved in reaction = (120 kJ / 2 mol) x (1.65 mol) = 99 kJ

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