# triangle XYZ has vertices (X(3, -1), Y(5,-4), and Z(1,-5). Then give the coordinates of X'Y'Z. 270 degrees counterclockwise about vertex x?

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- Φ² = Φ+1Lv 74 weeks ago
X' = X = (X_x, X_y)

Y' = (Y_y - X_y + X_x, X_x - Y_x + X_y)

Z' = (Z_y - X_y + X_x, X_x - Z_x + X_y)

X' = X = (3, -1)Y' = (-4 - -1 + 3, 3 - 5 + -1) = (0, -3)Z' = (-5 - -1 + 3, 3 - 1 + -1) = (-1, 1)

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