Calculus Gravity Question?
Hi, i have a practice problem i need help with.
- AlanLv 71 month ago
your first equation is position .
d(t) = 4.9t^2
but you want velocity = 98 m/s
v(t) = 9.8t
9.8t = 98
t = 98/9.8 = 10 seconds
now , plug 10 seconds back into your distance equation
d(10 seconds) = 4.9(10)^2 = 4.9*100 = 490 meters
so you need to be 490 meters high to reach
a speed of 98 m/s when you hit the ground
- nbsaleLv 61 month ago
The speed will be the derivative of the distance, so at time t the speed is
v(t) = d'(t) = 9.8t.
That fits with the physics, because the acceleration due to gravity is 9.8m/s^2.
Now find t such that v(t) = 98, and plug that value into d(t).
- 1 month ago
You need to contact YOUR teacher