# An elevator accelerates upward at 1.2 m/s 2 .?

.

The acceleration of gravity is 9.8 m/s

2

.

What is the upward force exerted by the

floor of the elevator on a(n) 68 kg passenger?

Answer in units of N.

If the same elevator accelerates downwards

with an acceleration of 1.2 m/s

2

, what is the

upward force exerted by the elevator floor on

the passenger?

Answer in units of N.

### 1 Answer

Relevance

- electron1Lv 71 month ago
There is one mistake in this problem. Since the elevator accelerates upward, the acceleration of gravity is -9.8 m/s^2. The net downward acceleration is 8.6 m/s^2. (9.8 – 1.2).

Net force = 68 * 8.6 = 584.8 N

This is the downward force that the passenger exerts on the floor of the elevator. According to Newton’s third law, upward force exerted by the elevator floor on

the passenger must be equal in magnitude. This is 584.8 N.

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