Anonymous
Anonymous asked in Science & MathematicsChemistry · 1 month ago

A 1.82 g sample of an unknown gas is found to occupy a volume of 1.46 L at... The molar mass of the unknown gas is __________ g/mol.?

A 1.82 gram sample of an unknown gas is found to occupy a volume of 1.46 L at a pressure of 772 mmHg and a temperature of 59 °C. Assume ideal behavior.

The molar mass of the unknown gas is __________ g/mol.

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  • 1 month ago
    Best Answer

    n=PV/RT = 772 mmHg * 1.46 L / 62.36 L∙mmHg/mol∙K * (59+273)K

    = 0.054438 mole

    molar mass= 1.82 g / 00.054438 = 33.43 g / mol ???

    unknown gas indeed

  • david
    Lv 7
    1 month ago

    PV = nRT ... n = PV / RT ... MM (molar mass) = mass / moles = m/n

    MM = m/n = m/[PV / RT] = mRT/PV

    MM = 1.82*62.4*332 / [772*1.86] = 26.3 g/mole

  • 1 month ago

    n = RT/PV = (62.36)(273.16+59) / (772)(1.46)

    molar mass = n/m

    where m is mass in grams

    you have a calculator....

    Ideal gas law

    PV = nRT

    n = number of moles

    R = gas constant = 0.08206 (atm∙L)/(mol∙K)

                       8.314 L∙kPa/mol∙K

                       0.08314 L∙bar/mol∙K

                       62.36 L∙torr/mol∙K

                       62.36 L∙mmHg/mol∙K

    T = temperature in kelvins

    P = absolute pressure in atm, kPa, bar, torr

    V = volume in liters

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